When a 1.0kg mass hangs attached to a spring of length 50 cm, the spring stretches by 2 cm. The mass is pulled down until the length of the spring becomes 60 cm. What is the amount of elastic energy stored in the spring in this condition, if g = 10 m/s 2
Text Solution
Verified by ExpertsThe correct answer is:
C
Force constant of a spring
⇒ ⇒ 
Increment in the length = 60 – 50 = 10 cm
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